Covid Pandemic and Long Queue - COVIDLQ Code Chef Easy Question

Welcome back to my blog , today we will discuss this easy question.

Here is the link to the PROBLEM .

So , the problem is very simple , we just need to find whether there are two people at distance less than 6 feet .

Just find the first person and then find the next person and if the distance is less than 6 , then break the code and then print NO otherwise continue the code and finally print YES .

Please take a look at the following code :-

#include <iostream>

using namespace std;

int main() {

    int t;

    cin>>t;

    while(t--)

    {

        int n;

        cin>>n;

        int arr[n];

        int x=1,count=6,j=0;

        int i=0;

        while(i!=n)

        {

            cin>>arr[i];

            i++;

        }

        i=0;

        while(arr[i]==0)

        {

            i++;

        }

        while(i!=n)

        {

            if(arr[i]==1)

            {

                if(count<6)

                {

                    x=0;

                    break;

                }

                else

                {count=0;}

            }

            count++;

            i++;

        }

        if(x==0)

        {

            cout<<"NO"<<endl;

        }

        else

        {

            cout<<"YES"<<endl;

        }

        

        

    }

// your code goes here

return 0;

}

For any doubts and queries , please write in the comments section .